[Type B] Chapter– 4 Class 12 CS – Sumita Arora Assignment | Q/A

Solution:

import tempConversion
print(tempConversion.to_centigrade(10)) # prefix is used in function call


from tempConversion import to_centigrade
print(to_centigrade(1))                  # no prefix needed

in program one the checkMain() is import as
import Allchecks

in program two the checkMain() is import as
from Allchecks  import checkMain()

Solution:

#
""" Module for basic calculations"""

def square(x):
    """Returns square of a number"""
    return x**2

def mul(x, y):
    """Returns product of two number"""
    return x*y

def div(x, y):
    """Returns division of two number"""
    return x/y

def fdiv(x, y):
    """Returns division of two number"""
    return x//y

def floordiv(x, y):
    return fdiv(x,y)

(a) function will accept a number as parameter not another function as argument. Hence, will occur.

(b) function need two argument but none of the given. Hence, error will occur.

(c) No error

(d) Division by zero will raise an error of not possible calculation.

(e) No error

(f) No error

(g) no error

(a) basics.square(19.23)
(b) basics.floordiv(1000.1, 100.23)
(c) basics.mul(5, basics.mul(3,4))
(d) basics.div(100, 0) will cause error as divisible by zero is not possible and second case will execute.

def diff():
    x = random.random() - random.random()
    return x

what would be the result is you now evaluate
    y = diff()
    print(y)
at python prompt?

Solution:

The output will be between -1 and 1 because random.random() give value between 0 and 1.

STRING = "CBSEONLINE"
NUMBER = random.randint(0, 3)
N = 9
while STRING[N] != 'L':
   print(STRING[N]+ String[NUMBER]+'#',end=" ")
   NUMBER = NUMBER+1
   N =N-1

(i) ES#NE#IO#    (ii) LE#NO#ON#   (iii) NS#IE#LO#   (iv) EC#NB#IS#

Solution:

The possible outcome of the above code will possible the two case
(i) ES#NE#IO# , (iv) EC#NB#IS# as the while code will run three time and will choose according to that and N will have (9, 8, 7) only.

import random
print(int(20+random.random()*5), end=" ")
print(int(20+random.random()*5), end=" ")
print(int(20+random.random()*5), end=" ")
print(int(20+random.random()*5)

(i) 20 22 24 25    (ii) 22 23 24 25    (iii) 23 24 23 24     (iv) 21 21 21 21

Solution:

So, the possible output of the above code will be (iii) 23 24 23 24 , (iv) 21 21 21 21

As random.random() will have value minimum and maximum 0 and 1 respectively.
Hence, the minimum value of above code will be 20 and maximum will be 25.

import random
print(100+random.randint(5, 10)), end=" ")
print(100+random.randint(5, 10)), end=" ")
print(100+random.randint(5, 10)), end=" ")
print(100+random.randint(5, 10))

Find the suggested output from options.

(i) 102 105 104 105 (ii) 110 103 104 105 (iii) 105 107 105 110 (iv) 110 105 105 110

Solution:

So, the possible output of the above code will be (iii) 105 107 105 110 (iv) 110 105 105 110
As random.randint(5, 10) will have value minimum and maximum 5 and 10 respectively. Hence, the minimum value of above code will be 105 and maximum will be 110.

(a) in this case to invoke writefile() the command will be
music.formats.wavwrite.writefile()

(b)in this case to invoke writefile() the command will be
wavwrite.writefile()

import random
PICK = random.randint(0, 3)
CITY = ["DELHI", "MUMBAI", "CHENNAI", "KOLKATA"]
for I in CITY:
    for J in range(1, PICK):
        print(I, end=" ")
    print()

(i)                           (ii)
DELHIDELHI                     DELHI
MUMBAIMUMBAI                   DELHIMUMBAI
CHENNAICHENNAI                 DELHIMUMBAICHENNAI
K0LKATAKOLKATA

(iii)                        (iv)
DELHI                        DELHI
MUMBAI                       MUMBAIMUMBAI
CHENNAI                      KOLKATAKOLKATAKOLKATA
KOLKATA

Solution:

The possible outcome can be (i) and (iv).
As the minimum value is 0 and maximum is 3. When range is 1 the pick will be 0 and nothing will be print same as pic is 1 but when it became 2 everything will be printed and for 3 everything will be printed twice.