# PRIP 1.2 Sumita Arora Solutions | Class 12 Computer Science

Here are PRIP 1.2 Sumita Arora Solutions for class 12 Computer Science. To view chapter 1 lecture videos, visit here.

To view Sumita Arora solutions for all chapters, visit here.

Q.1: In each of the following Python expressions or statements, indicate what data type belongs in the indicated place by choosing one of these data types:
`int, float, bool, str, list`
 Expression Correct Datatype (Answers) (a)    s = _______ + 17 int (b)   T = _______+’pie’ str (c)    x[______] = ‘catfood’ int (d)   ______.sort() list (e)   if ______ : bool
Q.2: What does Python print as it executes the following sequence of statements?
 Expression Correct Datatype (Answers) (a)    print((10+3)*2) 26 (b)   print(11/2) 5.5 (c)    x = 25        print(x*2 == 50) True (d)   print(x/2 >= 50) False (e)   a = ‘Honda’        b = ‘Audi’        print(a+b) HondaAudi (f)    c = len(a) + len(b)        print(c) 9 (g)    print(a) Honda (h)   print(a[1]) o
Q.3: What would be the output of following code?
`a = 9000            #initializes and assigns value to variableprint("Now it's a", type(a))a = float(a)print("Now it's a", type(a))a = str(a)print("Now it's a", type(a))`

`code:`a = 9000            #initializes and assigns value to variableprint("Now it's a", type(a))a = float(a)print("Now it's a", type(a))a = str(a)print("Now it's a", type(a))output:`#type function returns the type of variable passed as parameterNow it's a <class 'int'>Now it's a <class 'float'>Now it's a <class 'str'>`

Q.4: What would be the output of following code? Support your answer with reason.
`               x = 4               y = 8               z = x/y*y               print(z)`

`x = 4y = 8 z = x/y*y print(z)`

Explanation:

x/y = 4/8 = 0.5

0.5*y = 0.5*8 = 4.0

Q.5: Which of the following statements would yield 2? Assume that math module is imported. Recall that math.fabs() gives you absolute value of its arguments.
`a. print(5/2)`
`b. print(5.0//2)c. print((int)(5.0/2))d. print(math.fabs(-5.0/2))e. print(math.fabs(-5.0//2 ))f. print(math.fabs(-3//2))g. print(-5/2)h. print(-5/2)`
`i. print(-5//2)j. print(-5.0//2)`

`print((int)(5.0/2))gives output 2Note:maths.fabs(value)Parameter:value: variable / number / expressionReturns: the absolute value of the Parameter.5/2 gives 2.55//2 gives 2.0// is for floor division`

Q.6: Which of the following statements would yield 2.0? Assume that math module is imported. Recall that math.fabs() gives you absolute value of its arguments.
`a. print(5/2)`
`b. print(5.0//2)c. print((int)(5.0/2))d. print(math.fabs(-5.0/2))e. print(math.fabs(-5.0//2 ))f. print(math.fabs(-3//2))g. print(-5/2)h. print(-5/2)`
`i. print(-5//2)j. print(-5.0//2)`

`print(5.0//2)print(math.fabs(-3//2))gives output 2.0`

Q.7: What would be the output produced by the print statements given in previous questions?

`Code:print(5/2)print(5.0//2)print((int)(5.0/2))print(math.fabs(-5.0/2))print(math.fabs(-5.0//2 ))print(math.fabs(-3//2))print(-5/2)print(-5/2)print(-5//2)print(-5.0//2)Output:2.52.022.53.02.0-2.5-2.5-3-3.0`
Q.8: What would be the output of following?
(a)  print(type([1,2]))
(b) print(type(1,2))
(c)  print(type((1,2)))
(d) print(type(1/2))
(e)  print(type([1/2]))
(f)   print(type( (1/2)))
(g)  print(type( (1/2, )))

```Code:
print(type([1,2]))
print(type(1,2))
print(type((1,2)))
print(type(1/2))
print(type([1/2]))
print(type( (1/2)))
print(type( (1/2, )))

Output:
<class 'list'>
TypeError: type() takes 1 or 3 arguments
<class 'tuple'>
<class 'float'>
<class 'list'>
<class 'float'>
<class 'tuple'>

Note:
type() function takes 1 or 3 arguments
1. type([1,2])   [1,2] is one argument which is list
2. type(name,tuple,dict)```
Q.9: What would be the output of following?
x = True
y = False
z = False
print(x or y and z)

```or a b    a|b
0 0     0
0 1     1
1 0     1
1 1     1

and a b    a&b
0 0     0
0 1     0
1 0     0
1 1     1
= x or y and z
= True or False and False
= True or False
= True

Note:
According to the relative precedence levels of operators in programming
& is at higher priority than | that is why y and z executed first```
Q.10: Given the following Boolean variables, what would be the output of the following statements?
x = True
y = False
z = False
(a)  print(not x or y)
(b) print(not x or not y and z)
(c)  print(not x or y or not y and x)
(d) print(‘ant’ < ‘amoeba’)

`a)  print(not x or y)= not True or Flase= False or Flase= Falseb)  print(not x or not y and z)= not True or not False and False= False or True and False= False or False= False c)  print(not x or y or not y and x)= not True or False or not False and True= False or Flase or True and True= False or Flase or True= Flase or True = True d)  print('ant' < 'amoeba')a = abut n>m hence 'ant' < 'amoeba'i.e. 'ant' < 'amoeba' = Flase Note:While comparing strings with operators <=, >=, <, >The comparison is done character by character.`
Q.11: Write a program to find the side of a square whose perimeter you read from user.

`Code:perimeter = int(input("Enter perimeter of square : "))square_side = perimeter/4print("Side of square is {}".format(square_side))Output:Enter perimeter of square: 20Side of square is 5.0`

Q.12: Write a program to calculate the distance of 1056 feet in terms of yard and miles. Given fixed values are 1 mile = 1760 yards and
1 yard = 3 feet

`'''given 1056 feet1 mile = 1760 yards1 yard = 3 feet'''Code:feet = 1056yards = feet/3mile = yards/1760print("feet = {}".format(feet))print("yards = {}".format(yards))print("mile = {}".format(mile)Output:feet = 1056yards = 352.0mile = 0.2`

Q.13: An athlete is taking rounds of a triangular park with sides as 30m , 25m and 35m. The athlete has run 560m till now. Write a program to print how many rounds of park the athlete has complete.

`"""Given:sidesa = 30mb = 25mc = 35mapproach: first find perimeter of triangledividing 560m by perimeter will give number of rounds"""Code:a = 30b = 25c = 35distance = 560perimeter = a + b + crounds = distance / perimeterprint("Total rounds of ground : {:.2f} m ".format(rounds)) Output:Total rounds of ground : 6.22 m`
Q.14 Write a Python program that calculates and print on the screen the number of seconds in a year.

`Code:days = 365hrs = 24minutes = 60seconds = 60total_seconds = days * hrs * minutes * secondsprint("Total seconds in a year {}.".format(total_seconds))Output:Total seconds in a year 31536000.`

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